why matlab gave me 5 eigenvectors for 6*6 matrix?
2 ビュー (過去 30 日間)
古いコメントを表示
hi. i wanted to get eigenvectors of a 6*6 matrix. matlab must gave me 6 eigenvectors and 6 eigenvalues but it gave me 6 eigenvalues and 5 eigenvectors...
how is it possible?
clear;
syms x;
Ha='[x/2 0 0 0 0 0;0 -x/2 x 0 0 0;0 x -x/2 0 0 0;0 0 0 x/2 0 0;0 x 0 x 0 0;x 0 x 0 x 0]';
Haf = str2func(sprintf('@(%s)%s;','x',Ha));
[vectors,values]=eig(Haf(x));
vectors
0 件のコメント
採用された回答
KALYAN ACHARJYA
2019 年 12 月 27 日
編集済み: KALYAN ACHARJYA
2019 年 12 月 27 日
An nxn matrix M can have up to n unique eigenvalues and eigenvectors. If its characteristic equation det(M-lamda*I)=0 has repeated roots, then you get fewer than n eigenvectors
I have copied from here
1 件のコメント
Christine Tobler
2020 年 1 月 6 日
Note that this is true for the eig function used on symbolic variables. For numeric variables, you can rely on getting exactly n eigenvalues and eigenvectors from an n-by-n matrix.
This is because numeric algorithms are backward stable: For an input matrix A, they return eigenvalues and eigenvectors of a matrix B which is close to the matrix A (by about machine round-off error). There is always such a matrix B which has n eigenvalues and eigenvectors, and this is always chosen by the algorithms used in eig.
その他の回答 (0 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!