why matlab gave me 5 eigenvectors for 6*6 matrix?

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reza hamzeh
reza hamzeh 2019 年 12 月 27 日
コメント済み: Christine Tobler 2020 年 1 月 6 日
hi. i wanted to get eigenvectors of a 6*6 matrix. matlab must gave me 6 eigenvectors and 6 eigenvalues but it gave me 6 eigenvalues and 5 eigenvectors...
how is it possible?
clear;
syms x;
Ha='[x/2 0 0 0 0 0;0 -x/2 x 0 0 0;0 x -x/2 0 0 0;0 0 0 x/2 0 0;0 x 0 x 0 0;x 0 x 0 x 0]';
Haf = str2func(sprintf('@(%s)%s;','x',Ha));
[vectors,values]=eig(Haf(x));
vectors

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KALYAN ACHARJYA
KALYAN ACHARJYA 2019 年 12 月 27 日
編集済み: KALYAN ACHARJYA 2019 年 12 月 27 日
An nxn matrix M can have up to n unique eigenvalues and eigenvectors. If its characteristic equation det(M-lamda*I)=0 has repeated roots, then you get fewer than n eigenvectors
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I have copied from here
  1 件のコメント
Christine Tobler
Christine Tobler 2020 年 1 月 6 日
Note that this is true for the eig function used on symbolic variables. For numeric variables, you can rely on getting exactly n eigenvalues and eigenvectors from an n-by-n matrix.
This is because numeric algorithms are backward stable: For an input matrix A, they return eigenvalues and eigenvectors of a matrix B which is close to the matrix A (by about machine round-off error). There is always such a matrix B which has n eigenvalues and eigenvectors, and this is always chosen by the algorithms used in eig.

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