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How to find an equilibrium point between two lines?

12 ビュー (過去 30 日間)
Joao Pereira
Joao Pereira 2019 年 12 月 26 日
コメント済み: Rena Berman 2020 年 5 月 14 日
Hi guys could you help me find the equilibrium point between my demand and supply curves cheers.
This is the code I wrote, I tried using the command "solve", but I did not succeed
x = 1:20:14;
xticks(1:1:30)
y1 = -3*x +90;
plot (x,y1,'b')
hold on
x = 1:0.5:30;
y2 = 10+x;
plot (x,y2,'c')
hold on
x = 1:0.5:30;
y3 = -3*x +60;
plot (x,y3,'b')
plot (x,y1,y2,y3)
ylim([0 100])
hold on
legend ('0G demand curve','OG supply curve','tax(30)')
title ('Market Equilibrium')
xlabel('Quantitites')
ylabel('Price')
hold off
P = InterX([x1;y1],[x;y2]);
plot(x,y1,x,y2,P(1,:),P(2,:));
  1 件のコメント
Rena Berman
Rena Berman 2020 年 5 月 14 日
(Answers Dev) Restored edit

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回答 (1 件)

Mark Sherstan
Mark Sherstan 2019 年 12 月 26 日
You were close! The x domain must be the same length and some of your variables were mislabeled. I quickly cleaned up your code and this should work for you:
x = 1:0.5:30;
y1 = -3*x +90;
y2 = 10+x;
y3 = -3*x +60;
plot(x,y1,'b', x,y2,'c', x,y3,'b')
ylim([0 100])
title ('Market Equilibrium')
xlabel('Quantitites')
ylabel('Price')
P12 = InterX([x;y1],[x;y2])'
P23 = InterX([x;y2],[x;y3])'
hold on
plot(P12(1,1),P12(1,2),'ro')
plot(P23(1,1),P23(1,2),'ko')
legend ('0G demand curve','OG supply curve','tax(30)','Intersection Y1-Y2', 'Intersection Y2-Y3')
hold off
  5 件のコメント
Mark Sherstan
Mark Sherstan 2019 年 12 月 26 日
As long as the function and my code is in the same folder it will work, I just tested it. So if you need more help just ask!

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