フィルターのクリア

normalization cell array [1 -1]

3 ビュー (過去 30 日間)
haitham qutaiba
haitham qutaiba 2019 年 12 月 19 日
コメント済み: haitham qutaiba 2019 年 12 月 19 日
Dear all,
I have cell array called features got one row and four colunms,
features{1} = [-9 2 NaN 4 5 10];
features{2} = [2 -8.3 4 5 10];
features{3} = [8 NaN 10];
features{4} = [8 -4 9 9 2 1 3 10];
i would do normalization between 1 -1 based on this equation below, but this equation works with matrix not cell
features(:,1:end-1)=(features(:,1:end-1)-min(min(features(:,1:end-1))))/...
(max(max(features(:,1:end-1)))-min(min(features(:,1:end-1))));
i need a help how do normalization by ignoring last part of each cell which number 10 and NaN. and normolize it for the rest of numbers in cell.
thanks in advance.

採用された回答

Nicolas B.
Nicolas B. 2019 年 12 月 19 日
編集済み: Nicolas B. 2019 年 12 月 19 日
oh I see that you are mixing cell arrays and arrays. With your feature structure, to access the -9 of your first line, you need to do:
features{1}(1)
So, with your structure, if you want to continue that way, you should use this code:
% the normalisation function for 1 array
fnom = @(v) [(v(1:end-1) - min(v(1:end-1)))/(max(v(1:end-1))-min(v(1:end-1))), v(end)];
% apply your function on features cell array
features = cellfun(fnom, features, 'UniformOutput', false)
  1 件のコメント
haitham qutaiba
haitham qutaiba 2019 年 12 月 19 日
thank you so much Nicolas,

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by