Change color of stacked bars according to values

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Yasmin Samy
Yasmin Samy 2019 年 12 月 18 日
コメント済み: Yasmin Samy 2019 年 12 月 19 日
Hello,
I am trying to plot a stacked bar chart, where each bar has a color shade depending on values from another vector. I tried to use CData but failed..
bin_width is the bar widths that made the stacked bar chart with.
However, the color shade of each bar should depend on the values in mtot. I'm having trouble creating a new colormap that can be applied on my bar chart.
%reading input
mtot=table(3,:); %this is an array of size (1 x 32), these are the values that should define the color of the bars
% %tried to set a new color bar
% caxis([min_m max_m]);
% colorbar
% hold on
%plotting of stacked bar chart
% barcolor=c(size(mtot,2));
f=barh(0,bin_width','stacked','FaceColor','flat');
set(gca,'XScale','log');

回答 (1 件)

Xin Li
Xin Li 2019 年 12 月 19 日
Hi, Yasmin,
My understanding of your question is that you want to plot a horizontal stacked bar chart
with customized color for each bar. One way to achieve your goal is by setting 'FaceColor'
parameter for each bar using a for loop.
Here is an example, hope it is helpful.
load count.dat;
y = count(1:4,:); % y is a 4-by-3 matrix
width = 0.7;
colors = {'r', 'g', [0,0.5,0.5]}; % customized colors wrapped in a cell array, element could be either a color mark or a RGB vector
% set up colors
h = barh(y, width, 'stacked', 'LineStyle',':');
for i = 1 : 3
h(i).FaceColor = colors{i};
end
figure.jpg
For more information, please refer to barh function document.
  3 件のコメント
Xin Li
Xin Li 2019 年 12 月 19 日
編集済み: Xin Li 2019 年 12 月 19 日
It is easy to generate a clolor map with function cool.
Say, if you want to have 40 colors, just do
colors = cool(40);
assume mtot(1,1) = 3, then colors(3, :) is the actual color for that bar.
Yasmin Samy
Yasmin Samy 2019 年 12 月 19 日
Im sorry but can you clarify further. My problem is how to connect the values of mtot to colors that the bar takes accordingly. How do you write that in code?

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