Too many output arguments.

I've found this code that may help me a lot.

I cannot run, it keeps saying:

Error using type
Too many output arguments.

my version is 2014b

the code is

function [t,y]=valori(type)
a=340;
S=0.25;
x10=0.85;
U=144;

if (type == 1)
    
    Ac=0.0034;
    Vp=0.32;
    Lc=0.3;
    H=3.2613e4;
    W=0.3689;
    
else
    
    if (type == 2)
        
        Ac=0.0033;
        Vp=0.025;
        Lc=1.22;
        H=0.09e5;
        W=0.1;
    
    else
        
        Ac=0.0090;
        Vp=0.001;
        Lc=2.8;
        H=1.55e4;
        W=0.1587;
    
    end
    
end

[t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S);
end

function [t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S)

wh=a*sqrt(Ac/(Vp*Lc));  

B=U/(2*wh*Lc);  

k=x10-S*(x10-(1/3)*(x10.^3));   

[t,y]=ode45(@(t,y)greitzer10(H,W,B,U,Ac,y,S,k),[0 100],[0,0]);

subplot(2,2,1)
plot(t,y(:,1))
xlabel('t')
ylabel('\phi_c')
subplot(2,2,2)
plot(y(:,1),y(:,2))
xlabel('\phi_c')
ylabel('\psi')
subplot(2,2,3)
plot(t,y(:,2))
xlabel('t')
ylabel('\psi')
end

function dydt = greitzer10(H,W,B,U,Ac,y,S,k)
dydt = [ ((3*H*Ac*B)/(W*U))*((y(1)-(1/3)*((y(1).^3)))-y(2)); ((W*U)/(3*H*Ac*B))*(y(1)-(S*y(2)+k)) ];
end

this might be a missing part:

function y=carcomp(C0,H,x,W)
y=C0+H*(1+(3/2)*((x/W)-1)-(1/2)*(((x/W)-1).^3));

Answer 1

[per isakson]

I fail to reproduce the error you report

>> [t,y] = valori( 2 );
>> [t,y] = valori( 1 );
>> [t,y] = valori( 3 );

no error, no warning and produces a figure with three diagrams.

However

>> [t,y] = valori( type );
Error using type
Too many output arguments. 
>> 

"type" is the name of a function that doesn't return any output. Try

>> type=1; [t,y] = valori( type );

That works, but now you'll get unexpexted results if you try to use the function, type

Conclusion: Avoid to use function names as names of variables.

[Paul Rogers]

man, you made my day! Can't immagine how important this was to me.

One last thing, ho can I plot:

function y=carcomp(C0,H,x,W)
y=C0+H*(1+(3/2)*((x/W)-1)-(1/2)*(((x/W)-1).^3));
end

in the last missing quadrant?

[per isakson]

Add

%
C0 = 0;     % or a better value
cc = carcomp( C0, H, t, W );
subplot(2,2,4)
plot( t, cc )
xlabel('t')
ylabel('carcomp')

at the end of the function, valori. That fills the "missing quadrant", but maybe not with the data you expected.

[Paul Rogers]

function [t,y]=valori(type)
a=340;
S=0.25;
x10=0.85;
U=144;
if (type == 1)
    
    Ac=0.0034;
    Vp=0.32;
    Lc=0.3;
    H=3.2613e4;
    W=0.3689;
    
else
    
    if (type == 2)
        
        Ac=0.0033;
        Vp=0.025;
        Lc=1.22;
        H=0.09e5;
        W=0.1;
    
    else
        
        Ac=0.0090;
        Vp=0.001;
        Lc=2.8;
        H=1.55e4;
        W=0.1587;
    
    end
    
end
[t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S);
end
function [t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S)
wh=a*sqrt(Ac/(Vp*Lc));  
B=U/(2*wh*Lc);  
k=x10-S*(x10-(1/3)*(x10.^3));   
[t,y]=ode45(@(t,y)greitzer10(H,W,B,U,Ac,y,S,k),[0 100],[0,0]);
subplot(2,2,1)
plot(t,y(:,1))
xlabel('t')
ylabel('\phi_c')
subplot(2,2,2)
plot(y(:,1),y(:,2))
xlabel('\phi_c')
ylabel('\psi')
subplot(2,2,3)
plot(t,y(:,2))
xlabel('t')
ylabel('\psi')
end
function dydt = greitzer10(H,W,B,U,Ac,y,S,k)
dydt = [ ((3*H*Ac*B)/(W*U))*((y(1)-(1/3)*((y(1).^3)))-y(2)); ((W*U)/(3*H*Ac*B))*(y(1)-(S*y(2)+k)) ];
end

function y=carcomp(C0,H,x,W)
y=C0+H*(1+(3/2)*((x/W)-1)-(1/2)*(((x/W)-1).^3));
end

C0 = 0;     % or a better value
cc = carcomp( C0, H, t, W );
subplot(2,2,4)
plot( t, cc )
xlabel('t')
ylabel('carcomp')

then i type in the command

type=1; [t,y] = valori( type );

but it says this:

Error: File: valori.m Line: 63 Column: 1

This statement is not inside any function.

(It follows the END that terminates the definition of the function "carcomp".)

[per isakson]

"This statement is not inside any function." Why did you put it at the end of the file?

Read up on function and Local Functions

Here is a screen clip of the end of your file valori.m

Comments

• Upper left corner. With an indention of 4, I find it easier to see the scope of the functions.
• Upper right corner. The red box shows that the Code Analyzer has spotted a syntax error. Try to understand and fix that problem before running the code. See Check Code with the Code Analyzer
• The arrow points at the the end of the function valori.

Move the lines 61-66 to the end of the function valori.