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Mean of certain elements within a matrix

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Malik Khan
Malik Khan 2019 年 12 月 11 日
コメント済み: RAMPUNIT KUMAR 2021 年 9 月 1 日
I have a matrix which is a 372x6. Rather than find a mean for a specific row or a specific column, I want to find the mean of elements that lay in different rows as
Although the elements are from different rows, I have a pattern for the order in which they are to be taken. The last 2 elements (column 5 and 6) is to be averaged with the second third and fourth of the following row. The mean then needs to be found for each line. To make this easier to visualise I have written out a matrix for which we need to find 2 means. We need one mean to be of (e f h i j) and the other (k l m n o). For my case however I need to do this 371 times as we have 372 lines (obviously we can’t find mean for the first row).
(a b c d e f)
(g h i j k l)
(l m n o p q)
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RAMPUNIT KUMAR
RAMPUNIT KUMAR 2021 年 9 月 1 日
I too have a doubt, like for matrix
(a b c d e f g h I j k l m n o p q r)
I need to find the mean of a,b then c,d then e,f then g,h and so on upto last element. How could we do that if size is big enough.

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採用された回答

Stijn Haenen
Stijn Haenen 2019 年 12 月 11 日
I think this will work:
for i=1:371
Mean_i(i)=mean([matrix(i,5:6),matrix(i+1,2:4)]);
end

その他の回答 (2 件)

Bandar
Bandar 2019 年 12 月 11 日
編集済み: Bandar 2019 年 12 月 11 日
A=[1 2 3 4 5 6; 7 8 9 10 11 12;13 14 15 16 16 18;19 20 21 22 23 24]
[row,~]=size(A);
for i=1:row-1
c = A(i,[5 6]);
r = A(i+1,[2 3 4]);
B = [c r]
mean(B)
end
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RAMPUNIT KUMAR
RAMPUNIT KUMAR 2021 年 9 月 1 日
RAMPUNIT KUMAR less than a minute ago ⋮ I too have a doubt, like for matrix (a b c d e f g h I j k l m n o p q r) I need to find the mean of a,b then c,d then e,f then g,h and so on upto last element. How could we do that if size is big enough.

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Andrei Bobrov
Andrei Bobrov 2019 年 12 月 11 日
編集済み: Andrei Bobrov 2019 年 12 月 11 日
Here A - your array (m x 6)
[m,n] = size(A);
i = repmat((0:m-1)',1,n-1);
i(:,end-1:end) = circshift(i(:,end-1:end),-1);
i = [zeros(m,1),i];
lo = i ~= 0;
out = accumarray(i(lo),A(lo),[],@mean);
or
[m,n] = size(A);
i = [zeros(m,1),reshape(circshift(repelem(0:m-1,n-1),-2),n-1,[])'];
out = accumarray(i(i>0),A(i>0),[],@mean);
  1 件のコメント
RAMPUNIT KUMAR
RAMPUNIT KUMAR 2021 年 9 月 1 日
RAMPUNIT KUMAR less than a minute ago ⋮ I too have a doubt, like for matrix (a b c d e f g h I j k l m n o p q r) I need to find the mean of a,b then c,d then e,f then g,h and so on upto last element. How could we do that if size is big enough.

サインインしてコメントする。

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