What does z(1) and z(2) mean in that context?
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Hi guys,
I'm new to Matlab and I really need your help. I have following code:
z1_dot = @(t,z) 1/(R*C)*[((B-1)*z(1)-z(2));((2*B-1)*z(1)-2*z(2))];
Can somebody explain me, what z(1) and z(2) mean and how do they corellate with the z in @(t,z) .
Thank you very much in advance.
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Adam
2019 年 12 月 11 日
編集済み: Adam
2019 年 12 月 11 日
z(1) and z(2) mean the same as they would in any code - there is an expectation that z is an array with (at least) 2 values, otherwise it will error.
The z in @(t,z)
is what you must pass in to call that function, known as an anonymous function, which requires two input arguments, t and z, although since t appears to be un-used it is un-necessary. You would call it as e.g.
z1_dot( 7, [2 3] )
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