Calculate the time-averaged value every 10 iterations

Hi,

I do the calculation of X (k) 1000x1 in a time loop for t = 1: 10000 (note that X does not have an iteration t) and I want to put a condition when t = 9000 to compute the averaged value (in the time) of X every 10 iterations ot t and when t> = 9000 : 10000

I want to get the size of X average like that 1000x10 without introducing a time iteration t in the variable X

is there a way to do that?

Answer 1

[Nicolas B.]

I'm trying to understand your question. I understand that every 10 iterations, you want to display the average computation time of the last 10 iterations. So I would like to recommend you to do something like that:

% create t to go faster
t = NaN(1, 10);
it = 1;  % index in t array

for i = 1:10000
    tic;
    % your code
    t(it) = toc; % get the execution time for this sample 
                 % taking into account that i starts with 1
    it = it + 1;
    
    % display average time and reset counter
    if it == 10
        % compute and display average computation time
        fprintf('My average computation time = %f\n', mean(t));
        it = 1;
    end
end

% display last iterations if not already done
if it ~= 1
    fprintf('My average computation time = %f\n', mean(t(1:it)));
end

[m m]

my X(k) is calculated in this loop like this

for t =1:10000
    Xaveraged = 0; %initialization of the averaged value
for k = 1:1000
    X1(k) = ..
end
%here i need this condition
if t>=9000
    Xaveraged = Xaveraaged + X1
    
end
end
Xaveraged = Xaveraged /10000

i want to get Xaveraged in differebt steps of time.

there is a way to get this??