good evening family I was calculating the autocorrelation of the function cos (wt) but every time I compile I get an error like Error using plot Vectors must be the same length.
Help me please.
this is my code :
function autocorrx
f0=20; N=1000 ;
k=5; Tmax=k/f0;
t=0/2:Tmax/N:Tmax;
x=cos(2*pi*f0*t);
subplot(1,1,1);
plot(t,x);
axis([0 0.1 -1 1]);grid;
xlabel('t(s)');
ylabel('cos(wt)');
C = xcorr(x,x)*Tmax;
subplot(2,2,2) ; plot(t,C) ;
axis([-0 0.1 -1 1]);
grid
xlabel ('t') ;
ylabel ('Cxx(t)') ;
title ('autocorrelation ')
end

5 件のコメント

Adam Danz
Adam Danz 2019 年 12 月 9 日
That error means that "Vectors must be the same length". It's pretty clear.
K>> size(t)
ans =
1 1001
K>> size(C)
ans =
1 2001
Clearly t and C and not the same length. So Matlab doesn't know how to pair those coordinates which is required for plotting.
sabayke bremso
sabayke bremso 2019 年 12 月 9 日
thank you for your answer first the code has no more problem but I can not see autocorrelation of cos (wt) do you know why ???Capture.PNG
Adam Danz
Adam Danz 2019 年 12 月 9 日
Because you're crushing the axis limits.
axis([-0 0.1 -1 1]);
Remove that line.
sabayke bremso
sabayke bremso 2019 年 12 月 9 日
thank you sir sooooooooooooooooooooooooo much :0
Adam Danz
Adam Danz 2019 年 12 月 9 日
Glad I could help!

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 採用された回答

Adam Danz
Adam Danz 2019 年 12 月 9 日
編集済み: Adam Danz 2019 年 12 月 9 日

1 投票

The cross correlation function xcorr() will produce an output with 2*M-1 elements where M is the number of elements in the input. Perhaps you want to plot the results as a function of the lag.
[C,lags]= xcorr(x,x);
C = C*Tmax; % <--- this is from your code;
plot(lags,C);
Note that your subplots are not defined correctly. Assuming you want two vertically stacked subplot, the subplot definitions should be
subplot(2,1,1)
subplot(2,1,2)

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