To make coding simplier and have the same plot

Is there any ways to make my coding simplier at the same time keep my plot result as same as my original one?
retint05 = 5
retint1 = 10
retint2 = 20
retint3 = 30
dist05 = log([10:-1:1]+retint05);
dist1 = log([10:-1:1]+retint1)
dist2 = log([10:-1:1]+retint2)
dist3 = log([10:-1:1]+retint3)
eta05 = exp(-c*abs(dist05-dist05(:)));
discrim05 = 1./sum(eta05,1)
eta1 = exp(-c*abs(dist1-dist1(:)));
discrim1 = 1./sum(eta1,1)
eta2 = exp(-c*abs(dist2-dist2(:)));
discrim2 = 1./sum(eta2,1)
eta3 = exp(-c*abs(dist3-dist3(:)));
discrim3 = 1./sum(eta3,1)
hold on
plot(discrim05,'-mo','Displayname','interval = 5');
plot(discrim1,'-ro','Displayname','interval = 10');
plot(discrim2,'-go','Displayname','interval = 20');
plot(discrim3,'-yo','Displayname','interval = 30') ;
axis([0 length(dist) 0 1]) ;
title({'SIMPLE Memory Model'...
'\fontsize{9}\color{blue}Length = 10; Retetion Interval = 0'...});
xlabel('Serial Position','fontsize',14) ;
ylabel('Discriminability','fontsize',14);
lgd = legend ('Location','northwest');
lgd.NumColumns = 4;
lgd.FontSize = 6;
set(gcf, 'color', 'white');
hold off

 採用された回答

Rik
Rik 2019 年 12 月 8 日
編集済み: Rik 2019 年 12 月 9 日

0 投票

You could vectorize this, but using a loop is much easier and will probably have the same performance.
Here is an example for the code you posted:
c=20;%I added this to make the code run
retint_vector=[5 10 20 30];
plotcolors={'m','r','g','y'};%you can also omit this and let Matlab generate colors
for n=1:numel(retint_vector)
retint=retint_vector(n);
dist = log((10:-1:1)+retint);
eta = exp(-c*abs(dist-dist(:)));
discrim = 1./sum(eta,1);
hold on
plot(discrim,['-' plotcolors{n} 'o'],...
'Displayname',sprintf('interval = %d',retint));
hold off
end
axis([0 length(dist) 0 1]) ;
title({'SIMPLE Memory Model'...
'\fontsize{9}\color{blue}Length = 10; Retetion Interval = 0'});
xlabel('Serial Position','fontsize',14) ;
ylabel('Discriminability','fontsize',14);
lgd = legend('Location','northwest');
lgd.NumColumns = 4;
lgd.FontSize = 6;
set(gcf, 'color', 'white');
hold off

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2019 年 12 月 8 日

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Rik
2019 年 12 月 9 日

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