Formula Mean Values in Matlab code.
古いコメントを表示
Hello, can anyone help to write in Matlab code the formula below. The third term with the minus sine is a double sum.
(sum from i=1 to N of Xt-i*168)/N + (sum from j=1 to 7 of Xt-j*24)/7 -(sum of i=1 to n sum of j=1 to 7 of Xt-i*168-j*24)/(7*N).
thank you for your time
4 件のコメント
Azzi Abdelmalek
2012 年 9 月 29 日
編集済み: Azzi Abdelmalek
2012 年 9 月 29 日
what is Xt? its size?
Azzi Abdelmalek
2012 年 9 月 29 日
what are your index i or t?
aggelos
2012 年 9 月 29 日
回答 (1 件)
Image Analyst
2012 年 9 月 29 日
I don't think you've explained this correctly. What's the difference between t and i? Anyway, here's some code to get you started:
N = 100; % Or whatever. The number of elements.
T = 1 : N;
Xt = 2 * T; % Or whatever function of T that X is.
i = 1 : N;
theFirstSum = sum(Xt - (i * 168) / N)
5 件のコメント
aggelos
2012 年 9 月 29 日
aggelos
2012 年 9 月 29 日
Image Analyst
2012 年 9 月 29 日
OK. So, didn't I do that for the first sum? I just had to guess at Xt because you didn't tell us what it was - you replace that line with your actual Xt. Then you just basically do the same for the other sums. After all, it's your assignment so I can't just do everything for you and hand it over to you.
aggelos
2012 年 9 月 30 日
Image Analyst
2012 年 9 月 30 日
To sum the prior 168 items, in general
theSum = zeros(1, lastIndex);
for k = 168 : lastIndex
theSum(k) = = sum(Xt((k - 167) : k));
end
カテゴリ
ヘルプ センター および File Exchange で Debugging and Analysis についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!