Decision Branching Error in matlab onramp
45 ビュー (過去 30 日間)
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How to crack this error? The input data and solution provided by the matlab sources are same still the error is occuring.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/251819/image.jpeg)
9 件のコメント
prashant
約16時間 前
Modify the script so that the plotting code on lines 5–8 execute only if doPlot is 1
採用された回答
Steven Lord
2019 年 12 月 2 日
That might be checking that the densities that are printed as text when doPlot is 0 exactly match the densities that would be printed by "the code as shown above". The code you're using doesn't exactly match: note that your code doesn't display a space between "of" and the name of the element. Try adding the spacing before and after the element name (as I believe "the code as shown above" does) and see if that allows you to pass the test case.
4 件のコメント
Steven Lord
2019 年 12 月 17 日
Compare:
x = 1;
y = 2;
disp("The value of x is" + x + "and the value of y is" + y)
disp("The value of x is " + x + " and the value of y is " + y)
The two phrases displayed are not identical. If your code displayed the first of those phrases but the exercise expected the second your code would not pass the test.
Damilola Adeniji
2019 年 12 月 18 日
Hi Steve
Thanks for the quick response.
Even after following the phrase is still saying incorrect.
thanks.
![Capture.PNG](https://www.mathworks.com/matlabcentral/answers/uploaded_files/254966/Capture.png)
その他の回答 (5 件)
Ivan Derkunskii
2020 年 3 月 8 日
You'll be laughing, but you need just put spaces inside the phrases "The density of the" and "is" so that they look like "The density of the " (a space after the whole phrase) and " is " (spaces before and after the word).
8 件のコメント
Rahul Das A H
2022 年 2 月 5 日
load datafile
density = data(:,1);
if doPlot == 1
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
end
Walter Roberson
2022 年 2 月 5 日
Comparing to 1 is not necessary in the case where the values are guaranteed to be either 0 or 1.
In the case where the values are not guaranteed to be one of those two, then you need to know whether the rule is that the number must be exactly 1 to pass, or if the rule is that the number must not be zero to pass.
Bongani Tavengwa
2020 年 6 月 4 日
if doPlot
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
else
disp("The density of" + element + "is" + density)
end
3 件のコメント
Steven Lord
2020 年 6 月 4 日
name = "Bongani Tavengwa";
disp("Do you see the problem now" + name)
disp("Do you see the problem now " + name)
Do you see the difference in the two displayed statements? What's the difference between the second and third lines of code and what impact does that difference have in the displayed text?
Sreekanth K M
2020 年 6 月 17 日
if doPlot
plot(density)
title("Sample Densities")
xticklabels(element)
ylabel("Density (g/cm^3)")
else
disp(" The density of " + element + " is " + density)
end
6 件のコメント
Surya Karthik Nadupalle
2020 年 8 月 22 日
編集済み: Surya Karthik Nadupalle
2020 年 8 月 22 日
The problem is solved only when you give gaps between words in the bracket. Notice the spacing i gave. It worked
disp(" The density of " + element + " is " + density)
3 件のコメント
Walter Roberson
2021 年 6 月 25 日
We do not know what code you are using.
I also have not seen a copy of the question being asked.
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