# 2D Matrix revolution

6 ビュー (過去 30 日間)
Felipe Bayona 2019 年 11 月 18 日
コメント済み: darova 2019 年 11 月 19 日
Hi community
How can I revolutionize a 2D matrix around an axis to obtain a solid?
Supose a NxN matrix. In each row are the points of a kind of gaussian curve with less amplitude and higher width. Plotting this surface shows something like a half bell that decays to zero. (See Bottom)
I want to obtain a 3D image revolutionazing that matrix, so the solid looks like a complete bell, or a mexican hat.
Notice that each curve in the matrix rows are different.
I have already try with cylinder(), but i can't define the rotation axis, and the result is a segmented solid.
Possible solutions so I can get the 3D image and define the rotation axis?
Thanks a lot
The surface to revolutioniye looks like this:
Cylinder shows this:

#### 2 件のコメント

darova 2019 年 11 月 18 日
Which axis do you want to rotate?
Felipe Bayona 2019 年 11 月 18 日
I would like to know the general method, where i can specify the axis. In this particular example, I need to do it around the z-axis, to obtain the 'Mexican hat'

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### 回答 (2 件)

darova 2019 年 11 月 18 日
Use cylinder for each curve separately:
z = linspace(-1,1,20); % axis
[x,y,~] = cylinder(r,length(z)-1); % convert to cylinder system
zz = repmat(z',[1 20]); % create 2D matrix for Z matrix
surf(x,y,zz) % sphere

#### 4 件のコメント

darova 2019 年 11 月 18 日
attach the data
darova 2019 年 11 月 18 日
And what is the problem?
x = linspace(0,40,41);
[X,T, rc] = normalDiffusion(4, 1, 1, x, 20);
z = X(i,:); % axis
[x,y,~] = cylinder(r,length(z)-1); % convert to cylinder system
zz = repmat(z',[1 length(r)]); % create 2D matrix for Z matrix
surf(x,y,zz) % sphere
darova 2019 年 11 月 19 日
Maybe z and r should be switched?
z = X(i,:); % axis

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Philippe Lebel 2019 年 11 月 18 日

#### 1 件のコメント

Felipe Bayona 2019 年 11 月 18 日
This only alows to rotate a y=f(x) funtion
My matrix is composed by many curves, because my function is z=f(x,y)

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