MATLAB Answers

making array in for loop

4 ビュー (過去 30 日間)
Kangkeon Jeon
Kangkeon Jeon 2019 年 11 月 8 日
コメント済み: Kangkeon Jeon 2019 年 11 月 8 日
for k = 1:10000
[Score(k), Alignment{k}] = nwalign(p546ref,newones{k});
find_start_stop(Alignment);
find_every_deletion(Alignment);
end
this has "Unable to perform assignment because brace indexing is not supported for variables of this type." error. Why is that?
Score is integer and Alignment is 3x158 char array.

  2 件のコメント

Shubham Gupta
Shubham Gupta 2019 年 11 月 8 日
Alignment should be a cell type array to use
Alignment{k} % notice curly paranthesis, it is used cell type arrays.
Kangkeon Jeon
Kangkeon Jeon 2019 年 11 月 8 日
but i don't want to do Alignment(k), because every time i run that code, it should give 10 different Alignment of 3x158 char. I want the whole 3x158 char, not each character within one Alignment

サインインしてコメントする。

採用された回答

James Tursa
James Tursa 2019 年 11 月 8 日
Maybe prior to the loop define Alignment as a cell array to hold your results:
Alignment = cell(10000,1);

  1 件のコメント

Shubham Gupta
Shubham Gupta 2019 年 11 月 8 日
But using this means, losing the original data of Alignment which is a char array of (3x158)?

サインインしてコメントする。

その他の回答 (0 件)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by