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Surface area of sphere integral form

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Riley Copeland
Riley Copeland 2019 年 11 月 8 日
編集済み: Shubham Gupta 2019 年 11 月 8 日
I want to write a section of code that calculates the surface area of a sphere by solving the integral form. The ultimate goal is to change the limits of integration to find sections of the area. Problem is that the value of 'S' I'm getting is way off. Thanks for the help!
R = 1; % radius of sphere (m)
theta_1 = 0;
theta_2 = pi;
fun = @(theta) -cos(theta);
S = 4*pi*R^2*(integral(fun,theta_1,theta_2));

回答 (1 件)

Shubham Gupta
Shubham Gupta 2019 年 11 月 8 日
編集済み: Shubham Gupta 2019 年 11 月 8 日
Limits should be [0, pi/2] & fun should be sin
fun = @(theta) sin(theta);
S = 4*pi*R^2*(integral(fun,theta_1,theta_2/2)); % this will give correct answer

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