# How to find the maximum value for each 24 rows in an array?

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BN2 2019 年 11 月 4 日

Hello,
I have a 3d array, precip= :,:, 8760. in fact 8760 rows are available in one column. I want to find the maximum value in this column 24-by-24 in rows. And saving the bigger value and eliminate the smaller one. and do it for all 8760-row
so if the dimension before doing this is precip = :, :, 8760, after this work should be precip = :, :, 365.
I wanna practical this for a 3d array which the third dimension is what I talking about.
I'm attaching all my array. as the volume of original file is so big I cut first 72 rows and attach it
Thank you
##### 7 件のコメント表示非表示 6 件の古いコメント
BN2 2019 年 11 月 13 日
ok if assume that on this earth 1 day is of 2hr, then the output is:
Day = 1
T = 90
Day = 2
T = 900
I don't want to change the first and second dimensions.
input = :, :, 87600
output = :, :, 365 or 366

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### 採用された回答

Shubham Gupta 2019 年 11 月 14 日

According to the comments, you have provided, this will produce the desired output :
yd = max(max(mn2t)); % first find maximum for each hour
y = reshape(yd,24,1,size(yd,3)/24); % reshape it by day
output = max(y); % find maximum of each day
Let me know if this works !
##### 2 件のコメント表示非表示 1 件の古いコメント
Shubham Gupta 2019 年 11 月 14 日
Simply use for loop mn2t:
output = cell(size(mn2t));
for i = 1:length(mn2t)
mn2t_mat = mn2t{i}; % extract matrix of ith element
yd = max(max(mn2t_mat)); % first find maximum for each hour
y = reshape(yd,24,1,size(yd,3)/24); % reshape it by day
output{i} = max(y); % find maximum of each day
end
Output will be cell vector with each cell containing maximum of each cell of mn2t.

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### その他の回答 (1 件)

BN2 2019 年 11 月 14 日
Thank you ?

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