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I am really lost with this lab I have for Calculus 3, anyhelp would be great!

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Peter Pyrka
Peter Pyrka 2019 年 10 月 31 日
コメント済み: Walter Roberson 2019 年 10 月 31 日
Given:
f(x,y) = 4x + 2y - xy + 3x^2 -5y^2 +5
A = 2.4 , (B,C) = (-4.9,-6.8)
g(x,y,z) = y + z + 2xy + 2xz + 6yz - x^2 - 5z^2 - 4
Your code should consist of the following:
1. A sketch of the curve(s) satisfying f(x, y) = 0.
2. Compute the points of the form (A, y) that are on the curve. 1
3. Find an equation of the tangent line to the curve f(x, y) = 0 at each point of the form (A, y).
4. Draw a plot of this curve f(x, y) = 0 along with the tangent lines.
5. Using the computer software, find an equation of the form y = h(x) that represents this curve near the point with larger y coordinate, and use Calculus 1 techniques to find an equation of the tangent line at that point. In words, compare and contrast your two results.
6. Draw a sketch of the surface g(x, y, z) = 0.
7. Compute the points of the form (B, C, z) that are on this surface.
8. Find an equation of the tangent plane to the surface g(x, y, z) = 0 at each point of the form (B, C, z).
9. Draw a plot of this surface g(x, y, z) = 0 along with the tangent planes. It will likely be helpful to show one plot for each tangent plane.
  5 件のコメント
Peter Pyrka
Peter Pyrka 2019 年 10 月 31 日
I understand that helps me plot the equations, but how do i find points of the form(A,y)?
Walter Roberson
Walter Roberson 2019 年 10 月 31 日
solve(4*x+2*y-x*y+3*x^2-5*y^2+5,y) and substitute x=A

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