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How to set the diagonal of a cell array of matrices?

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Mohammed Kagalwala
Mohammed Kagalwala 2019 年 10 月 29 日
コメント済み: Mohammed Kagalwala 2019 年 10 月 29 日
Hi,
I'm looking to set the diagonal of my cell array to identity, specifically eye(3,3). I know a simple for loop solution exists, but if there's something more elegant please let me know.
Thank you.

採用された回答

Jos (10584)
Jos (10584) 2019 年 10 月 29 日
Well found, Mohammed! You should put as an answer here :-)
Here is another method
A = cell(4,4) % a cell array
n = size(A,1)
A(1:(n+1):end) = {eye(3,3)}

その他の回答 (1 件)

Mohammed Kagalwala
Mohammed Kagalwala 2019 年 10 月 29 日
I found the solution ! For a cell array A of size n x n, one can do the following
A(logical(eye(n,n))) = {eye(3,3)};

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