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Summation of vectors: use of sum function in loop

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jacob Mitch
jacob Mitch 2019 年 10 月 28 日
コメント済み: Shubham Gupta 2019 年 10 月 30 日
Say I have a a series %%(1/t)\sqrt{\sum_{k=1}^{s}(vector^t+vectortwo^t)^2}%% or (1/t)*sqrt of (sigma from t=1 to s) (vector^t+vectortwo^t)^3
Im tyring to do a summation of this but I'm not sure how i'm doing I have tried
vector=[1;2;3;4;5;6];
vectortwo=[1;3;4;5;6;8];
s=length(vector);
count=0;
for t=1:s
Value=sum(vector.^t+vectortwo.^t).^3
Newvalue=(1/t)*sqrt(Value);
count=count+Value;
end
Have I made an error somewhere in for loop

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Shubham Gupta
Shubham Gupta 2019 年 10 月 29 日
編集済み: Shubham Gupta 2019 年 10 月 29 日
I think
Newvalue=(1/t)*sqrt(Value);
should be outside the for loop :
vector=[1;2;3;4;5;6];
vectortwo=[1;3;4;5;6;8];
s=length(vector);
total=zeros(size(vector)); % change the name of the count
for t=1:s
Value=(vector.^t+vectortwo.^t).^3
total=total+Value;
end
NewValue = (1/s)*sqrt(total); % Output is 6x1 vector
Also, your mentioned series seems to be mathematically incorrect, since 't' can never be out of the "sigma". So, my understanding is it should be 's' instead of 't'
  2 件のコメント
Shubham Gupta
Shubham Gupta 2019 年 10 月 30 日
Glad I could help, if it solved your question, please consider accepting the answer

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