Output argument "y" (and maybe others) not assigned during call

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sanjay srinivaas
sanjay srinivaas 2019 年 10 月 27 日
コメント済み: Star Strider 2019 年 10 月 27 日
function y = ycal(x,x0,a)
gamma=0.021;
L=0.3*10^-2;
theta=0;
d=0.3*10^-3;
E=72*10^9;
I=3.976*10^-16;
A=2*gamma*cos(theta)*(2*a+d);
L1=x0;
offset=0.3*10^-3;
if(x<=L1)
y=(A/(E*I))*(x^3/6-(L1+a)*x^2/2)+offset;
elseif(L1<x&&x<=(L1+2*a))
T=(1+(L1)/2*a)/6;
U=(L1+a+(L1^2)/4*a)/2;
V=1/48*a;
W=L1^3/12*a;
X=L1^4/48*a;
y=(A/(E*I))*((x^3*T)-(x^2*U)-(x^4*V)+(x*W)-(1*X))+offset;
elseif((L1+2*a)<x&&x<=L)
Y=(L1^2+a*L1+(2/3)*a^2);
Z=((2/3)*L1^3+(2/3)*a^2*L1+(3/2)*a*L1^2+a^3/3);
y=(A/(E*I))*(-x*Y+Z)+offset
end
end
I'm getting this error"
Error in ycal (line 2)
gamma=0.021;
Output argument "y" (and maybe others) not assigned during call to "C:\Users\Admin\Documents\MATLAB\Proj\ycal.m>ycal"."
Could someone find the mistake please?

採用された回答

Daniel M
Daniel M 2019 年 10 月 27 日
編集済み: Daniel M 2019 年 10 月 27 日
What is the function supposed to return for y = ycal(1,0,0)? It doesn't pass any of the conditionals in the if statement. And since there is no default value for y, it cannot assign an output for y. Therefore, you need to handle the default value for y, perhaps by putting:
else
y = NaN;
end
Or something to that effect.
  1 件のコメント
Star Strider
Star Strider 2019 年 10 月 27 日
Assign ‘y’ first:
function y = ycal(x,x0,a)
y = NaN;
gamma=0.021;
... REST OF THE CODE ...
end

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