How to select a value in a matrix based on a pair of vectors?

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Francisco Francisco
Francisco Francisco 2019 年 10 月 23 日
コメント済み: Francisco Francisco 2019 年 10 月 24 日
For Example:
We have vectors:
girls boys
2 6
7 5
5 4
4 3
3 3
6 2
8 1
1 6
2 6
And a matrix C:
8 42 37 33 29 25
7 45 39 33 29 25
6 48 40 33 28 24
girls 5 50 40 33 27 24
4 49 38 31 26 22
3 43 34 27 23 19
2 32 25 20 16 13
1 15 11 8 6 5
1 2 3 4 5 6
boys
I would like to make a vector D where I take the value of the matrix C wich is referent to the pair of vectors girls and boys. For example:
girls boys vector D
2 6 48
7 5 29
5 4 33
4 3 38
3 3 34
ect...
  1 件のコメント
Jos (10584)
Jos (10584) 2019 年 10 月 23 日
I think you made a mistake. How is the value in the third column of D related to other values. I would have expected that for 2 girls and 6 boys, the element 13 would have been picked,rather then 48 ...
Also, why are there only 5 values for each number of girls in C, when there are upto 6 boys?
C cannot be a proper matrix btw. Is it a table with column and row names?

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採用された回答

Jeremy
Jeremy 2019 年 10 月 23 日
編集済み: Jeremy 2019 年 10 月 23 日
The easiest way I thought of was to use a loop. It's made awkward by the fact that your index for girls is the opposite of the default index matlab uses (i.e. 1,1 being the top-left matrix entry)
%% Vector Manipulation
girls = [2 7 5 4 3 6 8 1 2];
boys = [6 5 4 3 3 2 1 6 6];
%
C = [ 0 42 37 33 29 25;
0 45 39 33 29 25;
0 48 40 33 28 24;
0 50 40 33 27 24;
0 49 38 31 26 22;
0 43 34 27 23 19;
0 32 25 20 16 13;
0 15 11 8 6 5];
%
D = zeros(size(girls));
for i = 1:length(girls)
k = 9-girls(i);
D(i) = C(k,boys(i));
end
  3 件のコメント
Jeremy
Jeremy 2019 年 10 月 23 日
編集済み: Jeremy 2019 年 10 月 23 日
You would obviously need to modify the 9-girls(i) line if the dimensions of the problem are different. You could use length(girls) in place of the number 9, in this case, I think. Or [m n] = size(C) and then use m+1 in place of 9 (this might be the more correct solution).
Francisco Francisco
Francisco Francisco 2019 年 10 月 24 日
Offscorse I tried "length(girls)" and redimensioned the problem. But this is the error appears: "Index in position 1 is invalid. Array indices must be positive integers or logical values".
I am dealing with real numbers. Is that the problem?

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その他の回答 (1 件)

Steven Lord
Steven Lord 2019 年 10 月 23 日
If you don't want to use a loop like Jeremy Marcyoniak suggested, you could convert your subscripts into linear indices using sub2ind. As Jeremy pointed out, your data is arranged with the row indices in the reverse order of how the row indices increase in MATLAB, so you would need to either flip / flipud your data or reverse the polarity of your row indices. That's the k = 9 - girls(i); line in Jeremy's code. With the vectorized sub2ind version it would be k = 9-girls; or k = size(C, 1) + 1 - girls; to account for the number of girls not being fixed.
  1 件のコメント
Francisco Francisco
Francisco Francisco 2019 年 10 月 23 日
Thanks for the this effort. It answers part of the issue! However, those were a dummy data, and wneh I apply to my real data it doesn not work!
I would like that matlab to go to matrix C and picks the right combination values based on the pair A and B.
Please have a look at the attached excell file. I would like to fill the yellow column!

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