How to select a value in a matrix based on a pair of vectors?
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Francisco Francisco
2019 年 10 月 23 日
コメント済み: Francisco Francisco
2019 年 10 月 24 日
For Example:
We have vectors:
girls boys
2 6
7 5
5 4
4 3
3 3
6 2
8 1
1 6
2 6
And a matrix C:
8 42 37 33 29 25
7 45 39 33 29 25
6 48 40 33 28 24
girls 5 50 40 33 27 24
4 49 38 31 26 22
3 43 34 27 23 19
2 32 25 20 16 13
1 15 11 8 6 5
1 2 3 4 5 6
boys
I would like to make a vector D where I take the value of the matrix C wich is referent to the pair of vectors girls and boys. For example:
girls boys vector D
2 6 48
7 5 29
5 4 33
4 3 38
3 3 34
ect...
1 件のコメント
Jos (10584)
2019 年 10 月 23 日
I think you made a mistake. How is the value in the third column of D related to other values. I would have expected that for 2 girls and 6 boys, the element 13 would have been picked,rather then 48 ...
Also, why are there only 5 values for each number of girls in C, when there are upto 6 boys?
C cannot be a proper matrix btw. Is it a table with column and row names?
採用された回答
Jeremy
2019 年 10 月 23 日
編集済み: Jeremy
2019 年 10 月 23 日
The easiest way I thought of was to use a loop. It's made awkward by the fact that your index for girls is the opposite of the default index matlab uses (i.e. 1,1 being the top-left matrix entry)
%% Vector Manipulation
girls = [2 7 5 4 3 6 8 1 2];
boys = [6 5 4 3 3 2 1 6 6];
%
C = [ 0 42 37 33 29 25;
0 45 39 33 29 25;
0 48 40 33 28 24;
0 50 40 33 27 24;
0 49 38 31 26 22;
0 43 34 27 23 19;
0 32 25 20 16 13;
0 15 11 8 6 5];
%
D = zeros(size(girls));
for i = 1:length(girls)
k = 9-girls(i);
D(i) = C(k,boys(i));
end
3 件のコメント
Jeremy
2019 年 10 月 23 日
編集済み: Jeremy
2019 年 10 月 23 日
You would obviously need to modify the 9-girls(i) line if the dimensions of the problem are different. You could use length(girls) in place of the number 9, in this case, I think. Or [m n] = size(C) and then use m+1 in place of 9 (this might be the more correct solution).
その他の回答 (1 件)
Steven Lord
2019 年 10 月 23 日
If you don't want to use a loop like Jeremy Marcyoniak suggested, you could convert your subscripts into linear indices using sub2ind. As Jeremy pointed out, your data is arranged with the row indices in the reverse order of how the row indices increase in MATLAB, so you would need to either flip / flipud your data or reverse the polarity of your row indices. That's the k = 9 - girls(i); line in Jeremy's code. With the vectorized sub2ind version it would be k = 9-girls; or k = size(C, 1) + 1 - girls; to account for the number of girls not being fixed.
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