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Array indices must be positive integers or logical values.

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Dominic Nightingale
Dominic Nightingale 2019 年 10 月 23 日
回答済み: Johannes Fischer 2019 年 10 月 23 日
clc;
clear all;
x=1;
h=10;
f = @(x) sin(((x^2+x)))
for n = 1:10
df(n-1) = (f(x+(h^(n-1)) - f(x)))/(h^n-1)
end
not sure what I am doing wrong to get this error.

回答 (1 件)

Johannes Fischer
Johannes Fischer 2019 年 10 月 23 日
The first entry in any kind of Matlab vector/array/matrix... is indexed with 1 (and not 0, as for example in C++). That is why you get an error in the first iteration of your for loop.
Two options:
adjust the indieces for df
for n = 1:10
df(n) = (f(x+(h^(n-1)) - f(x)))/(h^n-1);
end
or, in Matlab you can get rid or the for loop and matalb calculates the resulting array in a single line, in many cases this is faster than usinng for loops
n = 1:10;
df = (f(x+(h^(n-1)) - f(x)))/(h^n-1);

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