Regexp question number two
3 ビュー (過去 30 日間)
古いコメントを表示
I have no idea why this isn't working. I've read in several places that this should work, but it doesn't. I have a string like:
str = 'Hello\nMy name is Lucas';
and I wanted to use regexp to split at the new line character, so I have the following:
results = regexp(str, '\n', 'split');
but it doesn't split the string and just returns the original string. I just upgraded to 2012b. Thanks.
0 件のコメント
採用された回答
Daniel Shub
2012 年 9 月 19 日
You need to escape the `\`
results = regexp(str, '\\n', 'split')
1 件のコメント
Matt Tearle
2012 年 9 月 19 日
To (hopefully) clarify: the "\n" in your string isn't actually a newline character -- it's just the two characters \ and n. So Daniel's solution is splitting on the literal combination of characters "\n".
If you had defined your string as
str = ['Hello',10,'My name is Lucas']
then the 6th character would actually be a line break and your regexp command would have worked.
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Characters and Strings についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!