If statement with or condition

Hi given the following code

BDR= [175 175 175 175 175 175 175 175 175 175 175 175 175];
SETTIMANA=[190 130 120 140 100 160 175 165 157 140 130 175 140 ];
NEXTpro = [25 60 50 40 30 30 30 35 10 34 23 45 12];
    

        if  (SETTIMANA(1) < BDR (1)) | (SETTIMANA(2)< BDR(2)) | (SETTIMANA(3)< BDR(3)) | (SETTIMANA(4)< BDR(4))| (SETTIMANA(5)< BDR(5))| (SETTIMANA(6)< BDR(6))| (SETTIMANA(7)< BDR(7))| (SETTIMANA(8)< BDR(8))| (SETTIMANA(9)< BDR(9)) | (SETTIMANA(10)< BDR (10)) | (SETTIMANA(11)< BDR(11))| (SETTIMANA(12)< BDR(12)) | (SETTIMANA(13)< BDR(13));  
        Y=NEXTpro
        else
        Y=NEXTpro
        SETT1 = SETTIMANA(1:numel(BDR));                                        % Equalise Vectors
        Y = Y(1:numel(BDR));                                              % Equalise Vectors
        idxy = SETT1 <= BDR;                                                % Logical Index Vecto 
        Y=BDR - SETT1;
        Y=Y.*idxy
        end
        

I cannot understand why the if condition cannot read the or operator in the right way.

The conditin is: if I have a value in SETTIMANA that exceed the value in BDR in the same column, then switch to condition else.

[Rik]

There is no loop in your code, so any line in your code can only execute once. Your conditional is equivalent to any(SETTIMANA<BDR), is that what you mean?

[KALYAN ACHARJYA]

Its perfectly working as you mentioned

What your condition exactly?

If any element of SETTIMANA< correcponding NEXTpro
%...^...Note here
% do
else
%do
end

or

If all element of SETTIMANA< correcponding NEXTpro
%...^...Note here
% do
else
%do
end

Which one

Also you can use logical indexing directly without mentioning one by one of SETTIMANA and NEXTpro

Answer 1

[Fabio Freschi]

if any(settimana < bdr)
    ...
else
    ...
end