Image Processing need to make an image circular
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Leslie Dominguez
2019 年 10 月 14 日
編集済み: Walter Roberson
2019 年 10 月 15 日
I was wondering if there is any way to crop an Image into a circular image I am using the mask function but i need it to be circular not just masked. This is my code I know i need some more work done but i need to figure this part first.
canvas=255*ones(3000,3000,3,'uint8');
A=imread('A.jpg');
F=imread('F.jpg');
C=imread('C.png');
E=imread('E.jpg');
A=A(:,200:1720,:);
C=C(9:1500,93:3093,:);
E=imresize(E,4);
I = E;
imageSize = size(I);
ci = [455, 450, 350]; % center and radius of circle ([c_row, c_col, r])
[xx,yy] = ndgrid((1:imageSize(1))-ci(1),(1:imageSize(2))-ci(2));
mask = uint8((xx.^2 + yy.^2)<ci(3)^2);
croppedImage = uint8(zeros(size(I)));
croppedImage(:,:,1) = I(:,:,1).*mask;
croppedImage(:,:,2) = I(:,:,2).*mask;
croppedImage(:,:,3) = I(:,:,3).*mask;
canvas(1:1080,1:1521,:)=A;
canvas(1510:3001,1:3001,:)=C;
canvas(1:720,1720:2999,:)=F;
canvas(900:1799,1050:1949,:)=croppedImage;
imshow(canvas)
採用された回答
Walter Roberson
2019 年 10 月 14 日
No. There are no data structures in MATLAB that are circular.
You have two choices:
- Masking (alphadata)
- Use a cell array with two columns, the second of which holds the pixels in this row of the image, and the first of which holds the offset to put the row at. There are no library routines to draw with such an image, but you could create one that used a separate graphics object for each row. With work you could probably create a single patch object with texture mapping (but it would sure be a lot easier to just use masking...)
2 件のコメント
Image Analyst
2019 年 10 月 15 日
編集済み: Image Analyst
2019 年 10 月 15 日
Make sure you don't mix up (x,y) with (row,column). Matrices are NOT indexed as matrix(x, y) - they are indexed as matrix(y, x).
Attach images A, F, C, and E if you need more help.
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