Convert transfer function to state-space models
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I'm trying to convert a transfer function to state space model. In order to avoid the control toolbox functions since I don't have it's license.
The transfer function that I'm using is quite simple. Is the model for a heatsink temperature.
For this transfer function I have the next values for A,B,C and D.
I've tried to compare the output from the lsim() function and the equations from above but the output differs

Here's the code that I've used
P = rand(1,10)*1000;
t = 0:1:length(P)-1;
A = -400;
B = 0.5;
C = 0.6658;
D = 0;
%%%%%%%%%%%%%%%%%%%%%%%%%
%%% State space %%%
%%%%%%%%%%%%%%%%%%%%%%%%%
state_space_sys = ss(A,B,C,D);
state_space = lsim(state_space_sys,P,t);
figure
plot(t,state_space)
grid on,grid minor, title('State space')
%%%%%%%%%%%%%%%%%%%%%%%%%
%%% My function %%%
%%%%%%%%%%%%%%%%%%%%%%%%%
x(1:length(P)) = 0;
y(1:length(P)) = 0;
u = P;
for k = 1:length(u)
x(k+1) = A*x(k) + B*u(k);
y(k) = C*x(k) + D*u(k);
end
figure
plot(t,y)
grid on,grid minor, title('My function')
Is there any mistakes on the approach?
It should be quite simple, but I can't manage to find the solution.
7 件のコメント
Walter Roberson
2019 年 10 月 16 日
編集済み: Walter Roberson
2019 年 10 月 16 日
Is there a reason not to use tf() and ss() ? That is, if you pass a tf into ss() then it will be converted.
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