## Why can't I solve this, it's simple. (Incorrect dimensions.... use .^) (I did then it says Invalid Operator.......)

さんによって質問されました 2019 年 10 月 9 日

### Steven Lord (view profile)

さんによって 回答されました 2019 年 10 月 9 日
Daniel M

### Daniel M (view profile)

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>> [x,y]=meshgrid(1:1:exp(5), -3:0.01:3)
>> z=((x+1)^y)-(x^y)
Error using ^ (line 51)
Incorrect dimensions for raising a matrix to a power. Check that the matrix is square and the power is a
scalar. To perform elementwise matrix powers, use '.^'.
>> z=((x+1)^.y)-(x^y)
z=((x+1)^.y)-(x^y)
Error: Invalid use of operator.

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R2019b

## 2 件の回答

2019 年 10 月 9 日

### Daniel M (view profile)

2019 年 10 月 9 日
採用された回答

This works fine:
z = ((x+1).^y)-(x.^y);
You should read a bit on the difference between array and matrix operations.

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2019 年 10 月 9 日
Thanks a lot, sorry newbie over here hehe

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### Steven Lord (view profile)

2019 年 10 月 9 日

The operator .^ (period followed by a caret) performs elementwise matrix power.
There is no operator ^. (caret followed by a period) in MATLAB. That can still be a valid sequence of symbols (the first example below shows one such use) but it is not valid in the context in which you're using it (the first part of the second and third examples.) The second part of the second and third examples show how you would perform those computations using the .^ operator.
2^.5 % 2 to the 1/2 power or sqrt(2)
x = 0.5;
2^.x % error
2.^x % sqrt(2)
y = 5;
2^.y % Nope
2.^y % 2^5 = 32

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