I have a an array.I need to find its index value.How can i do that?

1 件のコメント

Walter Roberson
Walter Roberson 2019 年 10 月 6 日
Is the index Circulated, Almost Uncirculated, or Mint Condition?

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KALYAN ACHARJYA
KALYAN ACHARJYA 2019 年 10 月 6 日
編集済み: KALYAN ACHARJYA 2019 年 10 月 6 日

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>> array_data=2:3:30
array_data =
2 5 8 11 14 17 20 23 26 29
Case 1: I assumed you are looking for index value of specific element in the array, say 17
idx=find(array_data==17)
Case 2: for all array Elements
idx=1:length(array_data)
Hope it helps!

10 件のコメント

Silpa K
Silpa K 2019 年 10 月 12 日
Is it possible to find the label value using this.
KALYAN ACHARJYA
KALYAN ACHARJYA 2019 年 10 月 12 日
編集済み: KALYAN ACHARJYA 2019 年 10 月 12 日
label value means?
Can you elaborate with example?
Silpa K
Silpa K 2019 年 10 月 12 日
If I have a dataset that contain 137 rows.I need to find the label value of each row.
Image Analyst
Image Analyst 2019 年 10 月 12 日
Unfortunately you forgot to provide the example KALYAN asked for. Please do so.
What is the label of each row? Is the label of row 87, 87 and the label of row 123, 123? If each label is just the index (i.e. row number), you could do
labels = 1 : size(m, 1);
Silpa K
Silpa K 2019 年 10 月 12 日
I have the following dataset ,In this dataset 1 st column is the set of labels that corresponding to the row.I need th find the labels row by row.
Walter Roberson
Walter Roberson 2019 年 10 月 12 日
The first column contains 1s and 2s. I am not clear on what you mean by finding the labels row by row?
T = readtable('ECGFiveDays_TRAIN.xlsx','readvariablenames',false);
labels = T{:,1};
Silpa K
Silpa K 2019 年 10 月 12 日
Find the label of 1st row next finding the label of second row or finding label of a specific row.
Walter Roberson
Walter Roberson 2019 年 10 月 12 日
After the code I posted had been executed, the label of first row would be labels(1). The label of second row would be labels(2). The label of the K'th row would be labels(K).
Silpa K
Silpa K 2019 年 10 月 13 日
Thank you sir.
KALYAN ACHARJYA
KALYAN ACHARJYA 2019 年 10 月 13 日
Answer Credit Goes to @Walter Sir

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