Help with Padovan Sequence
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I have a question that says
P(0)=P(1)=P(2)=1 , P(n)=P(n-2)+P(n-3)
use for loops to get a script for p(n)
I have written
function y=padovan(n)
P(1)=1; P(2)=1; P(3)=1;
for v=4:n
P(v)=P(v-2)+P(v-3);
end
y=P(n);
As you can see I have had to started at P(1)=P(2)=P(3)=1 instead of P(0)=P(1)=P(2)=1 as I get an error when trying to define P(0)=1, how would I change my script to include and start at P(0) instead of P(1) as I have done.
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採用された回答
David K.
2019 年 10 月 1 日
You cannot start at P(0) because matlab does not let you index at 0. However, you can make it so that it works as expected. Everywhere that you have n, replace it with n+1.
2 件のコメント
David K.
2019 年 10 月 1 日
I expect that is because it is part of the definition of the Padovan Sequence. Padovan of 0 still needs to be 1 even if matlab cannot nicely index at 0.
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