Modify a cell array referring to another cell array

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luca
luca 2019 年 9 月 24 日
コメント済み: luca 2019 年 9 月 24 日
Given the following code
G= {[1 2 1 2 1 2 3 4 5 4 5 4 6 3 9 3 9; 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85],[1 1 1 1 2 3 4 4 4 5 4 6 3 6 3 9; 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 ]};
SP= [1 2 3 4 5 6 9];
t1 = 20; t2 = 20 ; t3 = 20 ; t4 = 20 ; t5 = 20 ; t6 = 20 ; t7 = 20; t8=20 ; t9=20;
for i = 1:size (G,2)
result = cell(size(G));
for gidx = 1:numel(G)
[uval, loc1, ids] = unique(G{gidx}(1, :));
count = accumarray(ids, 1)';
result{gidx} = arrayfun(@(v, s, n) [repelem(v, n); s, zeros(1, n-1)], uval, G{gidx}(2, loc1), count, 'UniformOutput', false);
end
AB = G{i}(1,:);
end
With the value contained in the fist raw of each cell G, I want to modify the arrays contained in cell "result"
I for example we take the first raw of the first cell of G, reported as AB in each cycle:
1 2 1 2 1 2 3 4 5 4 5 4 6 3 9 3 9
at each iteration everytime I meet a specified element, I want to modify its array in result.
In particular, if I consider result{1, 1}{1, 1}" that was
1 1 1
5 0 0
Should now become
1 1 1
5+t1 5+t1+t1 5+t1+t1+t1
so
1 1 1
25 45 65
That is: every time I meet 1 in AB, I want to modify the values inside "result" that refer to that element and add everytime the value t1 to the previous one.
For element 2, at the beginning the result was
2 2 2
10 0 0
Then has to become
2 2 2
10+t2 10+t2+t2 10+t2+t2+t2
...
For element 9, at the beginning the result was
9 9
75 0
Then has to become
9 9
75+t9 75+t9+t9
I hope that it's clear what I would like to obtain
May someone help me with this task?
  4 件のコメント
Adam Danz
Adam Danz 2019 年 9 月 24 日
編集済み: Adam Danz 2019 年 9 月 24 日
The last example breaks your pattern. I think the last example should be
For element 9, at the beginning the result was
9 9
75 0
Then has to become
9 9
75+t9 75+t9+t9
% ^^^......^^^
luca
luca 2019 年 9 月 24 日
yes !

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採用された回答

Adam Danz
Adam Danz 2019 年 9 月 24 日
編集済み: Adam Danz 2019 年 9 月 24 日
Replace your t1,t2, t3... with this
tt = [20 20 20 20 20 20 20 20 20]; %Much easier to work with
Then replace the result{} line in the for(gidx...) loop with this
result{gidx} = arrayfun(@(v, s, n, t) [repelem(v, n); s + t.*(1:n)], uval, G{gidx}(2, loc1), count, tt(uval), 'UniformOutput', false);
% Changes > > > > > > > > > > > 1) ^ > > > > > > > 2) ^^^^^^^^^^ > > > > > > > > > > > > > > > 3) ^^^^^^^^

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