Add a row of zeros at the end of the matrix

Grateful for any help

x = [ 23 34 15 19]

actually i want the result to be a 4 by 2

23 0

34 0

15 0

19 0

Need to transpose x first. But unfortuantely I can't get the results.

My codes

new_A=zeros(size(x,1));

Answer 1

[the cyclist]

output = [x' zeros(4,1)];

You can generalize this a bit by using the numel function to determine and use the size of x to get the number of zeros, rather than hard-coding the number 4.

output = [x' zeros(numel(x),1)];

Answer 2

[Kevin Phung]

x = [23;34;15;19];
new_x = [x zeros(size(x))]