Attribute number to closed area

1 回表示 (過去 30 日間)
Armin Mashhadi
Armin Mashhadi 2019 年 9 月 9 日
コメント済み: Armin Mashhadi 2019 年 9 月 10 日
Hi,
I'm trying to calculate stable region automatically by Matlab. As shown in picture, Boundries are driven (as 2 vector of x,y) and split the plate into several closed areas.
Every closed area has a specific number and Somehow these numbers are related to each other.
I have to :
  1. Define very closed area
  2. Attribute an number (for example 2) for each Area
at last The area with least number is The stable region.
I have coordinates of intersections (Red Points), I was thinking about using these points and "inpolygon" command to find a point within The area and attribute the number to that point instead of whole surface. But Vertex Points are not connected Respectively (e.g 3th, 4th and 8th are making an area) and that does not work for me.
Could you please help me out of this ?

採用された回答

Bruno Luong
Bruno Luong 2019 年 9 月 9 日
編集済み: Bruno Luong 2019 年 9 月 9 日
You might checkout POLYSHAPE, that can give you the regions
P = polyshape(rand(10,2));
R = regions(P);
close all
plot(R);
for k=1:length(R)
[x,y]=R(k).centroid;
text(x,y,num2str(k));
end
polyshape.png
  3 件のコメント
Bruno Luong
Bruno Luong 2019 年 9 月 9 日
編集済み: Bruno Luong 2019 年 9 月 9 日
The white part is the complement of P: meaning the surounding rectangle substracted P. Checkout boolean operation of polyshape to get that complement.
Repeat the same process wuth the complement.
Box = polyshape([0 0;
1 0;
1 1;
0 1;
0 0]);
P = polyshape(rand(10,2));
Q = subtract(Box, P);
R1 = regions(P);
R2 = regions(Q);
R = [R1; R2];
close all
plot(R);
for k=1:length(R)
[x,y]=R(k).centroid;
text(x,y,num2str(k));
end
Split.png
Armin Mashhadi
Armin Mashhadi 2019 年 9 月 10 日
Thanks a lot, that worked for me ..

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeComputational Geometry についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by