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Diego R
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How can I assign several values from cell-array tovariables?

Diego R
さんによって質問されました 2019 年 9 月 4 日
最新アクティビティ Diego R
さんによって 回答されました 2019 年 9 月 5 日
I have the cell array from the example:
myNum = [1, 2, 3]; myCell = {'one', 'two'}; myStruct.Field1 = ones(3); myStruct.Field2 = 5*ones(5);
C = {myNum, 100*myNum; myCell, myStruct}
C = 2x2 cell array
{1x3 double} {1x3 double}
{1x2 cell } {1x1 struct}
I want to receive:
a=1
b=2
c=3
I've tried to do these, but didn't work:
[a,b,c]=C{1,1}
[a,b,c]=deal(C{1,1}(1,:))
I need to do in one time because my real code has dozens of values.
Thanks in advance for answers.

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3 件の回答

Kelly Kearney
回答者: Kelly Kearney
2019 年 9 月 4 日
 採用された回答

I think you'll need to use a quick intermediate variable so you can convert the numeric array to a comma-separated list:
tmp = num2cell(C{1,1});
[a,b,c] = deal(tmp{:})

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Star Strider
2019 年 9 月 5 日
In more recent MATLAB releases, deal isn’t necessary.
Just use:
[a,b,c] = tmp{:}

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Walter Roberson
回答者: Walter Roberson
2019 年 9 月 5 日

Unfortunately the temporary variable is still a practical necessity. It can be done away with, at cost:
[a,b,c] = subsref(num2cell(C{1,1}), struct('type', '{}', 'subs', {{':'}}))
but it becomes a lot easier if you define
VECEXPAND = @(VEC) VEC{:};
DEALVEC = @(VEC) VECEXPAND(num2cell(VEC));
[a, b, c] = DEALVEC(C{1,1})

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Diego R
Answer by Diego R
on 5 Sep 2019

Thanks a lot. It works. But it is a shame there isn't a direct way.

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