deleting a row based on index.
29 ビュー (過去 30 日間)
HbO_index = find(xyz1 > 7.5);%link the index with the HbO table and eliminate the bad channels
HbO_good_channel = HbO;
% for i = 1 : size(HbO,2)
for l = 1 : length(HbO_index)
k = HbO_index(l);
HbO_good_channel(:,k) = ;
HbO_index is matrix containing values which are basically index of HbO_good_channels which i want to remove.
Only the first column from HbO_good_channels it removing properly rest its removing one index prior to what is actually mentioned, it something to do with my logic. help me out please.
David 2019 年 9 月 3 日
The problem is that in your for-loop you delete the l-th column. Thereby all the indecies of the following columns change (are reduced by one). This happens in each iteration of the for-loop. If you want to remove columns "a, b, c, d" with your code you will actually remove columns "a, b+1, c+2, d+3".
You can solve your problem by starting the for loop on the end of "HBO_index" or without a for-loop:
HbO_good_channel = HbO
HbO_good_channel(:,find(xyz1 > 7.5)) = ;