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deleting a row based on index.

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CalebJones
CalebJones 2019 年 9 月 3 日
コメント済み: CalebJones 2019 年 9 月 3 日
HbO_index = find(xyz1 > 7.5);%link the index with the HbO table and eliminate the bad channels
HbO_good_channel = HbO;
% for i = 1 : size(HbO,2)
for l = 1 : length(HbO_index)
k = HbO_index(l);
HbO_good_channel(:,k) = [];
end
% end
HbO_index is matrix containing values which are basically index of HbO_good_channels which i want to remove.
Only the first column from HbO_good_channels it removing properly rest its removing one index prior to what is actually mentioned, it something to do with my logic. help me out please.
thank you
  2 件のコメント
madhan ravi
madhan ravi 2019 年 9 月 3 日
Attach your data as .mat file.
CalebJones
CalebJones 2019 年 9 月 3 日
編集済み: CalebJones 2019 年 9 月 3 日
I have attached the files below madhan ravi

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David
David 2019 年 9 月 3 日
The problem is that in your for-loop you delete the l-th column. Thereby all the indecies of the following columns change (are reduced by one). This happens in each iteration of the for-loop. If you want to remove columns "a, b, c, d" with your code you will actually remove columns "a, b+1, c+2, d+3".
You can solve your problem by starting the for loop on the end of "HBO_index" or without a for-loop:
HbO_good_channel = HbO
HbO_good_channel(:,find(xyz1 > 7.5)) = [];
  3 件のコメント
David
David 2019 年 9 月 3 日
You could also remove the "find" and use logical indexing for better performance:
HbO_good_channel = HbO
HbO_good_channel(:,xyz1 > 7.5) = [];
CalebJones
CalebJones 2019 年 9 月 3 日
Sure thank you David

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