How to remove zeros from an array without using nonzeros command

i want to delete the zeros without using nonzeros

x=[1 2 2 0 3 1 3 0 0];
i=1;
j=1;
while i <= length(x)
    if x(i)==0
        x(i) =[] ;
    else 
        x(i)=x(i);
end
while j <= length(x)
    if x(j)==0
        x(j) =[] ;
    else 
        x(j)=x(j);
end
j=j+1;
i=i+1;
end 
end
x

[Rik]

The code you show is not formatted correctly and it doesn't show an array, x is only a scalar. Are you sure this is what you mean?

[Dimitrios Adam]

sorry i forgot the space.For some reason it only deletes 1 zero if the are two one next to each other

Answer 1

[Rik]

If you insist on a loop: loop backwards through your array to account for removed elements.

x=[1 2 2 0 3 1 3 0 0];
for n=numel(x):-1:1
    if x(n)==0,x(n)=[];end
end

But course it is much better to do an array operation:

x(x==0)=[];

[Dimitrios Adam]

Thank you very much!!