Integers can only be combined with integers of the same class, or scalar doubles.

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Sajina Rose
Sajina Rose 2019 年 8 月 21 日
コメント済み: Guillaume 2019 年 8 月 21 日
red=I(:,:,1);
green=I(:,:,2);
blue=I(:,:,3);
R=(0.7*GRmean+(1-0.7)*LRmean);
G=(0.7*GGmean+(1-0.7)*LGmean);
B=(0.7*GBmean+(1-0.7)*LBmean);
r=red./R; %ERROR
g=green./G;
b=blue./B;
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Sajina Rose
Sajina Rose 2019 年 8 月 21 日
Yeah.....I defined formula for that in my code.......It's nothing but just global and local mean of RGB....
Ted Shultz
Ted Shultz 2019 年 8 月 21 日
What are your variable types? (command "whos") will tell you.
What error are you getting?

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回答 (1 件)

John D'Errico
John D'Errico 2019 年 8 月 21 日
READ THE ERROR MESSAGE!
R = uint8(1:5);
>> R./double(R)
Error using ./
Integers can only be combined with integers of the same class, or scalar doubles.
Is double( R ) a scalar double? In fact, it is not. It is a vector of doubles.
So MATLAB will not allow you to perform that operation. The information was completely contained in the error message, if you think about what it says and what you just did.
Can you fix it? Well, yes, that is trivial. In the line:
r=red./R;
Change it to read
r=double(red)./R;
red is a vector of INTEGERS. R is a vector of doubles. So to do that operation, you need to convert the vector red into a vector of doubles.
  1 件のコメント
Guillaume
Guillaume 2019 年 8 月 21 日
Another option would be to convert the original image to double with im2double:
I = im2double(I);
%rest of the code as it was
matlab expects images of type double to have intensities in the range 0-1, so im2double may be better than straight double conversion.
But yes, the error message explained what the problem is.

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