how create coordinate array?
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hi,
I found this function to plot the graph of adjacency matrix.
The input is adj matrix and coordinates array, xy. I have adj matrix , but I do not know how create coordinate array.
please can anybody help me in this regarding?
thanks
1 件のコメント
Oleg Komarov
2012 年 9 月 8 日
回答 (2 件)
nanren888
2012 年 9 月 8 日
huda nawaf,
Interesting that the Mathworks copyright is still in the code you are using. It is not clear what is added to gplot by the addition.
gplot has an example in doc: try doc gplot
It seems as a graph has no inherent shape, that you must provide the xy points for each node for it. The example in doc shows a Buckyball node layout.
I've never used gplot before. I read the help, read doc gplot, played a few minutes & have this.
x = 1:2;
y = 1:3;
[XX,YY] = meshgrid(x,y);
a = (rand([2*3,2*3])>0.8);
P=[XX(:),YY(:)];
gplot(a,P,'-*');
axis([0,7,0,7]);
a
P
a =
0 0 0 0 0 1
0 0 1 1 0 1
0 0 1 1 0 0
0 0 0 0 0 0
0 0 1 0 0 1
0 0 1 0 1 1
P =
1 1
1 2
1 3
2 1
2 2
2 3
Maybe it will help a little?
4 件のコメント
huda nawaf
2012 年 9 月 8 日
Walter Roberson
2012 年 9 月 8 日
Your earlier questions indicated that any outlay was acceptable. Are you now imposing restrictions about lines not overlapping, lines not crossing, or something like that?
huda nawaf
2012 年 9 月 9 日
Walter Roberson
2012 年 9 月 9 日
0 投票
If all you have is the adjacency matrix, then even if the weights of the vertices can be interpreted as distances, it is difficult to reconstruct a planar graph. Oh, algebraically it can be done, but it involves solving (N^2)/2 simultaneous non-linear equations, and that gets very time consuming extremely quickly.
So, you might as well just use rand() to generate random x and y coordinates and graph using those.
4 件のコメント
huda nawaf
2012 年 9 月 10 日
Walter Roberson
2012 年 9 月 10 日
random coordinates can do that.
huda nawaf
2012 年 9 月 13 日
Walter Roberson
2012 年 9 月 13 日
xy = rand(NumberOfNodes, 2);
I suspect that likely NumberOfNodes = size(AdjacencyMatrix, 1);
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