How do I invert nested functions in MATLAB?
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If I have a variable (let's call it a) and then I apply the following multiple functions to transform it into a second variable, (b), how would I reverse it?
b = fftshift(fftn(fftshift(a)));
I tried doing the following:
c = ifftshift(ifftn(ifftshift(b)));
If this had worked, c would have been equal to a (the initial, non-transformed data set). Why doesn't it? Is there a better, more universal way of reversing the function initially applied to A? I tried finverse, but it didn't work in the way I used it because fftshift works on doubles, and I was using a sym-type variable when I tried getting the inverse.
Any help is appreciated
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KALYAN ACHARJYA
2019 年 8 月 14 日
編集済み: KALYAN ACHARJYA
2019 年 8 月 14 日
"If I have a variable (let's call it a) and then I apply the following multiple functions to transform it into a second variable, (b), how would I reverse it?"
a=magic(3)
b = fftshift(fftn(fftshift(a)));
c = ifftshift(ifftn(ifftshift(b)))
Result:
a =
8 1 6
3 5 7
4 9 2
c =
8.0000 1.0000 6.0000
3.0000 5.0000 7.0000
4.0000 9.0000 2.0000
3 件のコメント
Walter Roberson
2019 年 8 月 14 日
編集済み: Walter Roberson
2019 年 8 月 15 日
Floating point roundoff. I suggest that you subtract the two versions and look at the difference.
fft involves the use of transcendental trig functions, so in order for the inverse to be always bit for bit exact, you would need to use indefinite precision.
You can use counting arguments to prove that if you use finite floating point that asin(sin(x)) cannot always exactly equal x even within the primary period.
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