Subtracting in matrix, column to column (Basic MatLab)?

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John wick
John wick 2019 年 8 月 11 日
コメント済み: John wick 2019 年 8 月 11 日
Given a 45×48 matrix, type a single command that subtracts column 36 from column 44
i answered this but it pops up as Error: Invalid use of operator. Is there something wrong or should it be in different type of form.
(:,36)-(:,44)

採用された回答

Star Strider
Star Strider 2019 年 8 月 11 日
Your idea is essentially correct. I have no idea what the question wants.
Perhaps providing a matrix and a reference to it will work:
A = rand(45,48);
col_dif = A(:,36)-A(:,44)
  6 件のコメント
John wick
John wick 2019 年 8 月 11 日
Ohhh Thank you very much for helping and explaining it. Love ya!
Star Strider
Star Strider 2019 年 8 月 11 日
As always, my pleasure!

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その他の回答 (1 件)

Image Analyst
Image Analyst 2019 年 8 月 11 日
編集済み: Image Analyst 2019 年 8 月 11 日
You need to put the matrix name in there, and a result variables, like
result = m(:,44) - .....................
etc.
  3 件のコメント
Image Analyst
Image Analyst 2019 年 8 月 11 日
Well you can't just have indexes within parentheses like (:,44), because how could MATLAB possibly know which matrix you're referring to.
John wick
John wick 2019 年 8 月 11 日
I guess i just got the idea on how it works but not really master it. Thank you for helping me out!

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