For loop within for loop

Please help me out. This code isn't working...
qq=8:10008;
for m = 1:9
for n = 1:10001
A(m, n) = (m+n)+qq;
end
end
I just want answer for A

3 件のコメント

Adam
Adam 2019 年 8 月 8 日
編集済み: Adam 2019 年 8 月 8 日
No idea what answer you want since you didn't tell us and you already said the code isn't working so there's not much point us looking at that to understand what you want.
However, you are adding a vector, qq, to a scalar (m+n) and trying to assign the result of this to a scalar A(m,n) which clearly will not work. At a guess you want to add qq(n) instead.
DARLINGTON ETAJE
DARLINGTON ETAJE 2019 年 8 月 8 日
You just solved the problem...qq(n) works....thank you.
Alex Mcaulley
Alex Mcaulley 2019 年 8 月 9 日
編集済み: Alex Mcaulley 2019 年 8 月 9 日
You can do it without loop. For example:
qq = 8:10008;
n = 1:10001;
m = 1:9;
[X,Y] = meshgrid(qq + n,m)
A = X + Y;
If you use the loops, at least preallocate your array A to minimize the execution time:
qq = 8:10008;
A = zeros(9,10001);
for m = 1:9
for n = 1:10001
A(m, n) = (m+n)+qq(n);
end
end

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回答 (1 件)

Jos (10584)
Jos (10584) 2019 年 8 月 9 日

1 投票

In recent ML versions there is no need for meshgrid or so. The plus syntax will expand the vectors :-)
% a smaller example
n = 1:11
m = 1:4
q = 8:18
A = m' + n + q

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2019 年 8 月 8 日

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2019 年 8 月 9 日

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