Indexing Based On Cell Array

randvar=cell(50,1);
for h=1:50
    randvar{h}=zeros(10,4);
    randvar{h}(:,1)=randi(10,10,1);       
    randvar{h}(:,2)=randi(5,10,1);              
    randvar{h}(:,3)=randi(10,10,1);            
    randvar{h}(:,4)=randi(17,10,1);            
end

for counter=1:15
    for h=1:50                             
        a{h}=0;                                 
        for i=1:10
            for j=1:10-i
                if  randvar{h}(i,1) ~= randvar{h}(i+j,1)
                    if randvar{h}(i,2)==randvar{h}(i+j,2)
                        if randvar{h}(i,3)==randvar{h}(i+j,3)
                            if randvar{h}(i,4)==randvar{h}(i+j,4)
                                a{h}=a{h}+10;
                            else
                                a{h}=a{h}+0;
                            end
                        end
                    end
                end
            end
        end
    end
end

[B, IX] = sortrows(a);
least = randvar(IX(1:10));

I don't quite understand why the IX returns 1. Shouldn't it return all the index of the cell array elements? I want to retrieve the first 10 least value for a for randvar.

P/S: My code works when I'm using cell2mat but because there're many loops, converting from cell2mat and mat2cell doesn't seem to be efficient.

[Andrei Bobrov]

a = cell(size(randvar));
for jj = 1:numel(a)
    x = randvar{jj};
    [b b c] = unique(x(:,1),'first');
    y = false(size(c));
    y(b) = true;
    z = x(y,2:end);
    [b b c] = unique(z,'first','rows');
    q = true(size(c));
    q(b) = false;
    a{jj} = nnz(q)*10;
end
[IX, IX] = sortrows(a);
least = randvar(IX(1:10));

or code for loop for..end

for h=1:50
    a{h}=0;                                 
    for i=1:10
        for j=1:10-i
            if  randvar{h}(i,1) ~= randvar{h}(i+j,1)&&...
                    isequal(randvar{h}(i,2:end),randvar{h}(i+j,2:end))
                a{h}=a{h}+10;
            end
        end
    end
end

Answer 1

[Arthur]

a is an matrix of 1 row and 50 columns. And like doc sortrow states: "If A is an m-by-n matrix, then B = A(index,:)."

So, initialize a like this, and you're fine:

a = cell(50,1);