simulink output size is not same as input size

im trying to run a model as a part of matlab code but, the ooutput of simulink 'temp' variable is not same as input variable 'temperature'
heres the code
m=size(test36New);
dt=10/(m(1)-1);
time=0:dt:10;
temperature=test36New.Var95;
t=[time' temperature];

3 件のコメント

Jim Riggs
Jim Riggs 2019 年 8 月 5 日
It is very hard to address this question without much information.
test36New is not defined, so we don't know what any of the variables are in your script.
We also don't know what output you are getting.
Also, there are no labels on the blocks in your Simulink diagram, so we can't tell what the blocks are.
Select all of the blocks, then right-click on the blocks, select Format \ Show Block Name.
Harish Medikonda
Harish Medikonda 2019 年 8 月 5 日
@Jim Riggs
test36New is a table which size can be seen in the picture attached.
simulink block, variable sizes can be seen in workspace tab in the screenshot provided.
the output I am getting is the same as input but the size of the array is different.
Thank you.
Harish Medikonda
Harish Medikonda 2019 年 8 月 5 日
the screenshot is attached to question.

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回答 (1 件)

Jim Riggs
Jim Riggs 2019 年 8 月 5 日

0 投票

The answer has to do with how you are saving variable "temp" from Simulink, but I cannot tell from the screenshot how this is being done.
If the "temp" block is a "to workspace" block, then there are a number of options for how to save temp, e.g. as an array, as a structure, as a time series, etc.
There are also options for how to concattenate multiple dimension signals (which also applies in this case).
One hint is that the value 51 is the (default) number of itteratons that the model is performing.

1 件のコメント

Harish Medikonda
Harish Medikonda 2019 年 8 月 5 日
ok. thank you very much. I just got it sorted.

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