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Point Spread Function with Gaussian (radial direction) and exponential (axial direction)

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poptrop459
poptrop459 2019 年 8 月 5 日
コメント済み: poptrop459 2019 年 8 月 6 日
A paper I'm reading had the following statement: "we can approximate the point-spread function by a Gaussian in the radial direction and an exponential with average height,d, in the axial direction."
Does anyone have any idea how this could translate into MATLAB code? I was thinking of generating random numbers from distributions and making a histogram, but the translation of the Gaussian/exponential combo to code itself is confusing me.

回答 (1 件)

Image Analyst
Image Analyst 2019 年 8 月 5 日
I don't know. You can use fspecial() to get a Gaussian image/pattern/matrix. Of course the values of that Gaussian are determined by the amplitude and standard deviation. I don't see how you can have it do that in the radial direction and have some other function in the axial direction. I don't even know what the axial direction is. Is that the distance along the optic axis from scene to lens/sensor/camera? Maybe the amplitude of the Gaussian changes along the optic axis according to an exponential. So your Gaussian close to the lens would be different than the Gaussian close to the scene. I've never heard of this though. Usually there is just one PSF for the whole system that takes everything into account no matter what caused it.
  3 件のコメント
Image Analyst
Image Analyst 2019 年 8 月 5 日
Try contacting the authors.
poptrop459
poptrop459 2019 年 8 月 6 日
Yep, I shot them an email. Hopefully I'll hear from them soon. Thanks for your help.

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