uint16 to uint8

Dear all,

I wonder whether there is an efficient way of converting an uint16 array of length N in an uint8 array of length 2N, so essentially replacing every 16bit word with two bytes:

e.g.

15000 => 58, 152

11000 => 42, 248.

The simplest implementation would be to convert decimal to binary string with 16 elements, and then split them 1..8 and 9...16, but I wonder if we can do another way.

Thank you in advance!

Answer 1

[James Tursa]

u16 = your uint16 variable
u8 = typecast(u16,'uint8');

[Svyatoslav Kharitonov]

Great! Thank you very much!

Answer 2

[Hiral Padhariya]

u8 = typecast(u16,'uint8');

[Walter Roberson]

What difference do you perceive between your answer and what James posted 2 1/2 years ago?