Hi,
I have installed MATLAB Support Package for IP Cameras and I am trying to connect a IP camera model FS-VCBOZ-4M (https://www.fs.com/file/datasheet/fs-vcboz-4m-datasheet.pdf) but I cannot connect, I always obtain the next problem:
>> camera = ipcam('http://IP:80', 'user', 'pass', 'timeout', 50);
Cannot connect to the IP Camera Stream URL. Make sure the URL is correct and authentication is provided if needed.
>> camera = ipcam('rtsp://IP:554', 'user', 'pass', 'timeout', 300);
Cannot connect to the IP Camera Stream URL. Make sure the URL is correct and authentication is provided if needed.
I have follow the instruction of https://es.mathworks.com/help/supportpkg/ipcamera/ug/connect-to-ip-cameras.html , and de connection with VLC media player works fine.
I don't know what is the problem, could you help me?

回答 (3 件)

Urmila Rajpurohith
Urmila Rajpurohith 2019 年 11 月 12 日

0 投票

The first input argument to “ipcam” function is URL.
The URL is made up of the IP address of the camera, followed by a video file designation, such as video.mjpeg or mjpg.cgi.
So, create a “ipcam”object as follows
camera = ipcam('http://IP:80/video.mjpeg', 'user', 'pass', 'timeout', 50);

4 件のコメント

Mariano Gonzalez de Soto
Mariano Gonzalez de Soto 2019 年 11 月 12 日
I also have proved it, but the part video.mjpeg or mjpg.cgi depends of the camera, in this case it works in the VLC without this part (http://user:pass@IP:80 works in VLC media player). But in matlab it does not work and, if i put it, I have the same result:
>> camera = ipcam('rtsp://IP:554/mjpg.cgi', 'user', 'pass');
Cannot connect to the IP Camera Stream URL. Make sure the URL is correct
and authentication is provided if needed.
>> camera = ipcam('rtsp://IP:554/video.mjpeg', 'user', 'pass');
Cannot connect to the IP Camera Stream URL. Make sure the URL is
correct and authentication is provided if needed.
>> camera = ipcam('http://IP:80/video.mjpeg', 'user', 'pass');
Cannot connect to the IP Camera Stream URL. Make sure the URL is
correct and authentication is provided if needed.
>> camera = ipcam('http://IP:80/mjpg.cgi', 'user', 'pass');
Cannot connect to the IP Camera Stream URL. Make sure the URL is
correct and authentication is provided if needed.
I think that it is relacionated with the camera model (IP camera model FS-VCBOZ-4M), maybe same especific URL, but i do not find this data
Urmila Rajpurohith
Urmila Rajpurohith 2019 年 11 月 20 日
can you provide the exact camera details which you used?
Mariano Gonzalez de Soto
Mariano Gonzalez de Soto 2020 年 3 月 4 日
The IP camera model is FS-VCBOZ-4M, more info in https://img-en.fs.com/file/datasheet/fs-vcboz-4m-datasheet.pdf
Lorenzo Giannini
Lorenzo Giannini 2020 年 12 月 9 日

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Konstantin Beckmann
Konstantin Beckmann 2021 年 4 月 8 日

0 投票

I have similar problem and still no solution. Can you help me?
I tried to read in two different IP Cams (Ubiquiti UniFi UVC G3 and a virtual camera via OBS Studio) independently.
It works with the VLC player, but not with Matlab. Unfortunately the matlab help could not help me either. I get the error: Cannot connect to the IP Camera Stream URL. Make sure the URL is correct and authentication is provided if needed.
I entered the URL from the interface (stand alone mode) of the camera or from the OBS-Studio into VLC and in VLC the video is displayed. I also checked the codec information from the VLC. Compared to the matlab help I have 2 streams, but the video stream is H264 (see pictures).
Code for connecting to virtual camera:
cam=ipcam('rtsp://localhost:554/live')
Code for connecting to UniFi camera:
cam=ipcam('rtsp://xxx.xxx.xxx.xxx:xxx/s0','user','pw'
What am I doing wrong?
Thanks for your help!

1 件のコメント

Roberto
Roberto 2022 年 7 月 6 日
@MathWorks Support Team Do you have a solution for this? I have the same problem.

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