how to compare a single row with remaining all rows of a matrix?

my input matrix is v=[1 2 3 4 5;3 4 7 8 9;6 4 8 7 9;3 4 7 8 9;3 2 9 8 4]; I am taking second row alone. I have to compare it with all the remaining rows. How to do it. Suggest me simple code which has few lines.

[Azzi Abdelmalek]

wha should be you result? a matrix?

[Jan]

What have you tried so far? Which problems occurred? What does "compare" exactly mean?

Answer 1

[Andrei Bobrov]

out = ismember(v,v(2,:),'rows');

[Sivakumaran Chandrasekaran]

Your reply matches my requirement exactly. Thanks Andrei bobrov.. And I thank all the people who spend their time to answer my query.

Answer 2

[Azzi Abdelmalek]

v=[1 2 3 4 5;3 4 7 8 9;6 4 8 7 9;3 4 7 8 9;3 2 9 8 4]
v2=v(2,:);
comp=any(bsxfun(@minus,v,v2),2))

%the result:

   comp=1     0     1   0    1

that means that fourth row (comp(4)=0) is equal to the second row

[Jacek]

For the future generations: I tested both solutions and solution proposed by Azzi is much faster, exactly 9x faster in my application, what was very important for me (large-scale data structures reorganization).