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acces data in struct

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Rica
Rica 2019 年 7 月 19 日
コメント済み: Mario Chiappelli 2019 年 7 月 19 日
Hi!
I have a struct Str. the element of the structure arle A, B, C,.... all of the are arrays with length 2000. I want to have onle the element from 500:1500 without writing
Str.A1=Str.A(500:1500) for every struct element.
is there an easy way to achieve this goal?
thank you!

採用された回答

Peter Jarosi
Peter Jarosi 2019 年 7 月 19 日
編集済み: Peter Jarosi 2019 年 7 月 19 日
You can use for loop indexing elements of your structure:
myElements = fieldnames(Str);
% or you can list your elements
% myElements = {'A', 'B', 'C'};
for x = 1 : length(myElements)
e1 = myElements{x};
e2 = strcat(e1, '1');
Str.(e1)=Str.(e2)(500:1500);
end
Please, let me know if it works for you
  2 件のコメント
Peter Jarosi
Peter Jarosi 2019 年 7 月 19 日
You're very welcome!
You are right, if you want to overwrite your existing instances. In this case strcat() is even unnecessary:
myElements = fieldnames(Str);
% or you can list your elements
% myElements = {'A', 'B', 'C'};
for x = 1 : length(myElements)
e1 = myElements{x};
Str.(e1)=Str.(e1)(500:1500);
end
but in your question you wrote:
Str.A1=Str.A(500:1500);
that's why I thought that you want to create new elements of your structure in order to save old ones.

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その他の回答 (2 件)

Mario Chiappelli
Mario Chiappelli 2019 年 7 月 19 日
編集済み: Mario Chiappelli 2019 年 7 月 19 日
I would loop through each A,B,C... Other languages call this a for each loop.
for str = {'A','B','C'}
variableName = strcat(str{1},'1');
Str.(variableName) = Str.(str{1})(500:1500);
end
Note: Instead of looping through numbers where each iteration is stored in the for statement variable "i" (or whatever you decide to call it), you are looping through each letter and the for statement variable in this case is "str".
  6 件のコメント
Mario Chiappelli
Mario Chiappelli 2019 年 7 月 19 日
*thumbs up emoji

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Rica
Rica 2019 年 7 月 19 日
Thank you to every one!

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