How to integral a composite function in yalmip?

2 ビュー (過去 30 日間)
Tong Liu
Tong Liu 2019 年 7 月 13 日
コメント済み: Tong Liu 2019 年 7 月 15 日
sdpvar x1 x2 x3 u1
% syms x1 x2 x3 u1
d=x1+x2;
y=x1+x2+u1+d;
z=y+3;
t=int(z,y,0,y)
hello everyone...I have define a integration by yalmip, but there are some error..
If replace by syms, there are still errors.
Could you please help me find the mistakes? THANKS.

採用された回答

infinity
infinity 2019 年 7 月 13 日
Hello,
You define z as a function of x1, x2, and u1. But, you apply the integral function to compute the integral of z over the interval [0, y] and told the integral function that the variable of z is also y. It is not correct.
Let image that what you are doing like trying to compute
  3 件のコメント
infinity
infinity 2019 年 7 月 15 日
Hello,
In case, we have function z(y) = y + 3 then we can compute the integral of z with respect to y as simple by
syms y a
z = y + 3;
res = int(z,y,0,a)
where "a" is upper limit of the integral.
But, in your given code, you defined z as function of x1, x2, u1 and parameter d. Matlab can not understand that z is a function y.
Tong Liu
Tong Liu 2019 年 7 月 15 日
Get it. Thank you for your kindly help!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeNumerical Integration and Differential Equations についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by