read data from file and convert to a 3d array.

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vampcj 2019 年 7 月 5 日

So, I have a dat file storing a 3d data (131*385*97), the data is store in form below:
a(1,1,1),a(1,1,2)...........a(1,1,97)
a(1,2,1),a(1,2,2)...........a(1,2,97)
. . . . . . . . . . .
a(1,385,1),a(1,385,2)...........a(1,385,97)
a(2,1,1),a(2,1,2)...........a(2,1,97)
. . . . . . . . . . .
a(131,385,1),a(132,385,2)...........a(131,385,97)
My question is how I read this form of data and store it as a 3d array in matlab?

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回答 (2 件)

Abhishek Kumar 2019 年 7 月 8 日

I am attaching the code below this works for data (3*3*3), make changes accordingly to suit your purpose.
Also, If you wish to read data from a dat file, you will have to use the function importdata(..)
>> help importdata
a = reshape(1:27, 3, 9) .'; % here i have data which is 9*3
i=1;
m=1;
n=1;
o=1;
for j =1:9
o=1;
for k=1:3
A(m, n, o)=a(j,k);
o=o+1;
if mod(j, 3)==0 && i~=3 && k==3
o=0;
n=0;
m=m+1;
end
end
n=n+1;
end

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Rik 2019 年 7 月 8 日

To suggest the best way to read the file, you will have to share a small sample. Otherwise functions like importdata or the more low-level textscan will probably do the job.
For the parsing of the data once you have read the file, you can use the code below. As you can see with the check at the end, the output is as expected. There is no way to automatically determine how many rows and columns there are, so you will have to provide at least one of the two. The number of pages is simply the second dimension of your input, and once you have rows or cols you can divide the length of the second input by the one to obtain the other.
cols=3;rows=4;pages=5;
data=reshape(1:cols*rows*pages,cols*rows,pages);%generate random data
%each cell is the third dimension
b=mat2cell(data,ones(1,size(data,1)),size(data,2));
b2=reshape(b,rows,cols)';
flip_to_third_dim=@(x) permute(x(:),[3 2 1]);
out=cellfun(flip_to_third_dim,b2,'UniformOutput',false);
out=cell2mat(out);
%check:
isequal(out(1,1,:),flip_to_third_dim(data(1,:)))

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