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Filtered by matrix columns

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Lev Mihailov
Lev Mihailov 2019 年 7 月 5 日
閉鎖済み: Jan 2019 年 7 月 5 日
a = this is my maximum
r = is his position
c = new variable if r is validfor
[a,r]=max(FF);
or i = 1:length(a)-1
f(i)=0;
if (r(i) >= r(i+1))
c(i)=r(i);
else (r(i) <= r(i+2))
c(i)=r(i);
end
end
I already asked a similar question, but my task became somewhat more complicated.
The essence of the problem, as I know, is that the first position is correct r (1) = 200, but all the others need to be checked, r (1) is more or less r (2) +50, r (2) = 240, the test passes, then r (2) with r (3), etc. r(3)=700
  2 件のコメント
KALYAN ACHARJYA
KALYAN ACHARJYA 2019 年 7 月 5 日
A Problem Well-stated is Half-solved
Guillaume
Guillaume 2019 年 7 月 5 日
For reference this is the previous question: comparison of columns in the matrix.
Once again, you've given us code that makes no s, this time it's not even valid. Rather tha explaining what you want with nonsensical code, explain in words and with examples.
What are you trying to do? An example of input and desired output would really help.

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